I'm using sigma notation and this is what it breaks down to: p(k) is k^3= (k^2(k+1)^2)/4
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Originally Posted by Edbaseball17 I'm using sigma notation and this is what it breaks down to: p(k) is k^3= (k^2(k+1)^2)/4 What would i do to get p(k+1)
Originally Posted by Edbaseball17 I'm using sigma notation and this is what it breaks down to: p(k) is k^3= (k^2(k+1)^2)/4 Are you asking how to show that ? The base case is n = 1: and so this checks out. Now we assume the theorem is true for some n = k. That is: So we want to show this for n = k + 1. You need to show that this is the same thing as: -Dan
kinda, but the right side is all over 4, not just the 1
Originally Posted by Edbaseball17 kinda, but the right side is all over 4, not just the 1 sorry, just have to learn how to make all the fancy characters, lol.
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