# Thread: Chromatic Polynomial: Does anyone else get the same answer as me?

1. ## Chromatic Polynomial: Does anyone else get the same answer as me?

I lost my notes which included the answer to this question, so I was just wondering if I had done it correctly:

I get:

$k(k-1)^2(k-2)^2 - k(k-1)(k-2)^2 - k(k-1)(k-2)^2$

$= k(k-1)^2(k-2)^2 - 2k(k-1)(k-2)^2$

$=k(k-1)(k-2)^2(k-3)$

Thanks.

2. ## Re: Chromatic Polynomial: Does anyone else get the same answer as me?

I computed it and got to the same answer.