# Total relations between sets proof

• Nov 14th 2011, 04:15 PM
Total relations between sets proof
Question: Suppose a set A has n elements and a set B has m elements. Prove that there are 2^m*n different relations from A to B

Now i see how this works with the product rule with AXB with m*n elements. and there are two sets so thats where 2 is involved. So i guess all the pieces are there but i don't know what to do with them.(Worried)
• Nov 14th 2011, 04:27 PM
Plato
Re: Total relations between sets proof
Quote:

Question: Suppose a set A has n elements and a set B has m elements. Prove that there are 2^m*n different relations from A to B

I use $\|A\|$ as the notation for the number of elements is a set $A$.

Then $\|A\times B\|=\|A\|\cdot\|B\|$

Any subset of $A\times B$ is a relation $A\to B$.

So the answer to this question is $2^{\|A\|\cdot\|B\|}$
• Nov 14th 2011, 07:14 PM
Re: Total relations between sets proof
How do you get to the point where you come to the conclusion where you use '2' to get '2^||A||*||B||' ? I'm confused on that jump.
• Nov 15th 2011, 03:39 AM
Plato
Re: Total relations between sets proof
Quote:

If S is a set, the number of subsets of S is $2^{\|S\|}$.
If we form the set of bit-strings, strings of 0's & 1's, of length n, then that set has $2^n$ elements.
If $S=\{a,b,c,d\}$ then the string $0,1,1,0$ represents the subset $\{b,c\}$. So every 4-bit-string represents a subset of $S$ so there are $2^4$ subsets of $S$.