5 people stand in line..
A)how many way are there to arrange these people
B)if A and B must stand together, how many ways are there to arrange these people
C)what is the probability A and B stand together
i think i may have this one figured out, but would like some confirmation that i did it correctly
B) i grouped A and B together making my sample AB,C,D,E
-then i did P4/4=4!=24
-then i considered that AB can be grouped in two ways so did p2/2=2!=2
-then i multiplied the results 24x2=48 combinations
is this correct?
i appreciate any input