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Math Help - Gödel numbering

  1. #1
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    Gödel numbering

    The following is a solved problem:




    So, I don't understand how they got the 37 from...
    We assign numbers to each symbols using the rules here. We get:

    13(7+8)(13+8.2^3.3^1)(7+8)(7+8)(7+8)

    So when we place these as exponents of odd prime numbers we get:

    2^{13} \times 3^{15} \times 5^{205} \times 7^{15} \times 11^{15} \times 13^{15}

    The third term evaluates to 205, so why did they use 37?
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  2. #2
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    Re: Gödel numbering

    I agree with you; the third exponent should be 205.
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  3. #3
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    Re: Gödel numbering

    Thanks, maybe that's a typo.
    Last edited by demode; October 19th 2011 at 09:58 PM.
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