8 people are in an elevator that goes up 6 floors. All 8 people exit the elevator by the 6th floor. The elevator operator is in the elevator watching them exit (the elevator operator does not count as one of the 8 people)

How many ways can the people exit the elevator if they are all identical?

This would just be $\displaystyle \binom{6+8-1}{6-1} = \binom{13}{5} $

If there were 5 men and 3 women and the elevator operator could tell the men from women, how many ways could they exit the elevator?

Men = $\displaystyle \binom{5+6-1}{6-1} = \binom{10}{5} $

Women = $\displaystyle \binom{3+6-1}{6-1} = \binom{8}{5} $

Thus, # of ways to exit = $\displaystyle \binom{10}{5} * \binom{8}{5} $

Now what if the elevator operator could distinguish each person (i.e. nobody is identical)

Would this just be $\displaystyle 6^8 $

Thanks for any help!