Re: Combinatorial problem

Quote:

Originally Posted by

**Dinkydoe** I like to show that this problem is equivalent with finding the number of solutions of:

There are ways to place *N* identical objects into *K* distinct cells.

Here we have fourteen identical 1's and five distinct variables.

If we go ahead and put two of the ones into each of that leaves eight 1's to place anywhere.

Re: Combinatorial problem

That shows that the number we're looking for is

But I don't see how these 2 problems are equivalent. How do they relate..?