Find 5 elements that could be in:
{x ∈ ℤ|x - 3 ≡ 0 (mod 2) }
Given ᵋ = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}, find A' given A = {1, 4, 7, 9}
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Find 5 elements that could be in:
{x ∈ ℤ|x - 3 ≡ 0 (mod 2) }
Given ᵋ = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}, find A' given A = {1, 4, 7, 9}
Are these two different questions? Is ᵋ the universal set, and is A' the complement of A?
What have you tried and what are your difficulties? Do you understand all the concepts involved?
Yes. They're two different questions. I did the first one though. I don't understand the second one. I think we can assume that ᵋ is just a set that includes 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and that A' is the complement of A.Quote:
Originally Posted by emakarov
Also, for the first one, correct me if I'm wrong. I came to the conclusion that basically the elements that could be in there were odd numbers, so I listed odd numbers.
I agree.Quote:
Also, for the first one, correct me if I'm wrong. I came to the conclusion that basically the elements that could be in there were odd numbers, so I listed odd numbers.
My guess is that the second question asks to find the complement of {1, 4, 7, 9} when the whole (universal) set is {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}.
Yes, that's the conclusion I've come to. Thanks for your time and your help.Quote:
Originally Posted by emakarov
Just tagging on here.Quote:
Find 5 elements that could be in:
{x ∈ ℤ|x - 3 ≡ 0 (mod 2) }
Would 13,15,17,19,21 be a correct answer to this question?
Could it not just be any odd number?
Yes, any odd integer is in the set.