Hi guys, need with with this question:

In how many ways can 5 gentlemen, involving Roy and Ben, and 5 ladies, including Jane, be seated at a round table, such that - Jane sits next to neither Roy nor Ben?

This is how I did it:

Case 1 - Jane sits next to Roy

Grouping Jane and Roy, no.of ways = (9!/9) * 2! = 80640

Case 2 - Jane sits next to Ben

No.of ways = (9!/9) * 2! = 80640

Taking complement,

(10!/10) - 2(80640) = 201600

Is my method wrong? Thanks in advance!