I'm trying (and failing) to find a counterexample to the following false theorem:

For all functions from Reals to Reals, if is monotonic, then at least one of or is a monotonic function.

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- Apr 19th 2011, 06:45 PMjameselmore91Counter Example for Theorem about Monotonic Functions
I'm trying (and failing) to find a counterexample to the following false theorem:

For all functions from Reals to Reals, if is monotonic, then at least one of or is a monotonic function. - Apr 19th 2011, 08:38 PMTKHunny
How about f(x) = asin(1/x) and g(x) = 1/x? Or are this f and g monotonic?

- Apr 20th 2011, 08:17 AMjameselmore91
I guess this will work, but since asin(1/x) is undefined from x = (-1, 1) it technically isn't a function on the reals. It's only a function from R - (-1, 1) to R.

If I come up with no other examples this will do, but I feel there should be an example with a true function from R to R - Apr 20th 2011, 01:39 PMawkward
How about f(x) = 1 if x is rational, -1 if x is irrational, and g(x) = x^2?

- Apr 20th 2011, 08:02 PMTKHunny
I was tryng to come up with something at least mostly continuous.