Thread: factorials

hi,

how do i do (2n-1)!/(2n+1)!

Write this way (2n-1)! and (2n+1)!, then simplify and see what remains.

so for (2n-1)! = 2n-1.2n where else for (2n+1)! = 2n+1.2n ?

O.o No. You really read the first line?

n! = the product of first n natural unzero numbers. So... (2n-1)!=?

salohcinseah,

I guess you din't get what veileen actually said.
See



So



Similarly



So, now divide both and see what remains.

i see so the answer will be 1/(2n+1)?

amul28 - uhm, >.>



The answer will be .

my bad.
you are correct.
salohcinseah, please correct that.