how do i do (2n-1)!/(2n+1)!
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Write this way (2n-1)! and (2n+1)!, then simplify and see what remains.
so for (2n-1)! = 2n-1.2n where else for (2n+1)! = 2n+1.2n ?
O.o No. You really read the first line?
n! = the product of first n natural unzero numbers. So... (2n-1)!=?
I guess you din't get what veileen actually said.
So, now divide both and see what remains.
i see so the answer will be 1/(2n+1)?
amul28 - uhm, >.>
The answer will be .
you are correct.
salohcinseah, please correct that.
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