Show:
$\displaystyle \sum^{\infty}_{n=2} \frac{1}{f_{n-1}f_{n+1}} = 1$
i think we have to use the fact that
$\displaystyle \frac{1}{f_{n-1}f_{n+1}} = \frac{1}{f_{n-1}f_{n}} - \frac{1}{f_{n}f_{n+1}} (for \ n \geq 2)$
no idea where to start!
Show:
$\displaystyle \sum^{\infty}_{n=2} \frac{1}{f_{n-1}f_{n+1}} = 1$
i think we have to use the fact that
$\displaystyle \frac{1}{f_{n-1}f_{n+1}} = \frac{1}{f_{n-1}f_{n}} - \frac{1}{f_{n}f_{n+1}} (for \ n \geq 2)$
no idea where to start!