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Math Help - Is this a permutation?

  1. #1
    s3a
    s3a is offline
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    Is this a permutation?

    In order to determine the number of strings that can be formed by ordering the letters in "GUIDE", do I do P(6,5) = 6!/1! = 6! = 720 or am I wrong?

    If I'm right, please tell me so that I can know otherwise, please tell me what I'm doing wrong and how to do it correctly.

    Any help would be greatly appreciated!
    Thanks in advance!
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  2. #2
    Super Member TheChaz's Avatar
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    Where did you get the 6 from? There are 5 letters in guide...
    5!
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  3. #3
    Member Haven's Avatar
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    Using your notation, I want to find all order the letters G,U,I,D,E. So, I wish to find all orderings involving all of the letters. Since there are five letter in GUIDE. So, we use P(5,5) = 5!. Or, "5 pick 5", as professors often say.

    Now if I wanted all strings of length 3, by ordering the same letters, I would use P(5,3) = \frac{5!}{(5-3)!} = 5*4*3 = 60 . Or rather, "5 pick 3"
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