I am having problems understanding as to why n+r-1 C n-1= n+r-1 C r?
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Originally Posted by qwerty10 I am having problems understanding as to why n+r-1 C n-1= n+r-1 C r? Because $\displaystyle \dbinom{N}{k}=\dbinom{N}{N-k}$. $\displaystyle (n+r-1)-(n-1)=r$
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