Hey all,
Given
Is
?
And also how can I prove that for all sets and we have
What is the cardinality of A (denoted |A|)? The cardinality of P(A) is 2^|A|, so what you wrote is missing a few. Also, the elements of P(A) are subsets of A, so there's no way that 1 is an element of P(anything), since it's not a set.
I think once you get the first part straightened out, the second part won't give you much trouble.