I don't quite understand the question as written.
Are you saying that ?
Series Q is an arithmetic series such that the sum of its first n even terms is more than the sum of its first n odd terms by 4n. Find the common difference of the series Q. The answer provided is 4.
Can you help me? Thanks.
In that case you will need to consider two cases.
Case 1: Your series has an odd number of terms, which means will be on the RHS.
Case 2: Your series has an even number of terms, which means will be on the LHS.
Let's look at Case 1:
(Excluding the term), each side of the equation is an arithmetic series.
Since there were an odd number of terms in your original series, that means there are terms on the LHS, and terms on the RHS.
Can you sum these two smaller arithmetic series?
P/S: I have difficulty in forming an appropriate equation to find the common difference... can you help me..?
If there are an odd number of terms, that means on the LHS there will be one less term than on the right.
How many terms are there on each side? Well, if you halve an odd number, you'll get a remainder of . This extra half will have to go to the right hand side.
That means the LHS will have terms, and the RHS will have terms.
Also, do you see that each term on the LHS will have its own common difference, which is twice the common difference of your original series? Same on the RHS. That means they are both arithmetic series...
How do you sum an arithmetic series?
OK, so that we don't get confused, for our original series we'll use lowercase letters, and for each of the smaller series I'll use capitals...
You're saying that to sum each arithmetic series, use the formula .
Now, the difference , where is the difference from the original series.
Working with the LHS... We have already established that , and we should note that .
Now try to arrive at a similar expression for the RHS.