When there is no restriction, the possible number of ways is simply 9!.
When the first 3 must be boys, these 3 boys can sit in 3! ways and the rest 6 can sit in 6! ways. Hence the total number of possible ways in this case is 3!*6!.
quite confused with this particular question...
How many ways can 9 students(5 girls and 4 boys) be seated in a row if
there are no restrictions and if the first 3 must be boys?
i think its the difference in number of boys and girls that is confusing me
How many ways can 5 girls and 4 boys be seated in a row
if the first 3 must be boys?
Select three of the four boys: . choices.
Seat them in the first three chairs: . ways.
Seat the other six children: . ways.
Therefore, there are: . ways.