ok given the boolean expression F= X'Y+XYZ'

a. derive an algebraic expression for F'

ive found the one above

F= X'Y+XYZ'

=(X'+Y)(X+Y+Z')

=(X'+Y')(X'+Y'+Z)

THEREFORE F'= (X+Y')(X'Y'+Z)

NOW SHOW THAT F.F'=0

AND F+F'=1

THIS IS WHERE I AM AT PAUSE.. (Headbang)