while missing the squares F2 and E3,
so it advances 3 left and 3 up in 2 moves, from (1,1) to (4,4).
Therefore it will get to (10,10) in 6 moves.
It takes 56 more moves to get to (94,94).
On a normal board, it would be on H1 let's say,
trying to get to A8 in the least number of moves.
It cannot do so directly as described, so it takes a detour via
H1 to G3 to H5 to F4 to D5 to B6 to A8.
As this takes only one move more than if it could have continued it's previous
hopping mechanism, (which could not be continued with),
that is the shortest number of jumps.
EDIT: Sorry, I just noted from your post that my horse is going the wrong way!
No matter, just reel the tape backwards.