Hi

I'm trying to understand how to solve this type of equation and don't know.

A*exp(x/B)+Cexp(x/D)+Fexp(x/G)+Kexp(x/L)+Mexp(x/N)=0

I need to find x.

Thanks for your help,

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- Jan 29th 2011, 11:17 AMJesyHow to solve equation with many exp
Hi

I'm trying to understand how to solve this type of equation and don't know.

A*exp(x/B)+Cexp(x/D)+Fexp(x/G)+Kexp(x/L)+Mexp(x/N)=0

I need to find x.

Thanks for your help, - Jan 29th 2011, 11:55 AMemakarov
Welcome to the forum.

If one of B, D, G, L, N is a multiple of the rest, then this problem reduces to finding roots of a polynomial. For example, suppose that B = d * D = g * G = l * L = n * N for some positive integer d, g, l, n. Then $\displaystyle e^{x/D}=e^{(x/B)\cdot d}=(e^{x/B})^d$. So, the equation becomes $\displaystyle Ay+Cy^d+Fy^g+Ky^l+My^n=0$ for $\displaystyle y=e^{x/B}$.

Do you need to solve this equation symbolically or numerically? Is there some background knowledge that you need to use? Also, depending on these answers, you need to post this question to the right forum (this one is about discrete mathematics). - Jan 29th 2011, 12:06 PMJesy
Thank you, that is what I needed. I'll try to work it out