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Math Help - 3 lines 9 wrenches

  1. #1
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    3 lines 9 wrenches

    3 lines are to divide up 9 wrenches evenly.

    \displaystyle\frac{9!}{(3!)^3}=1680

    I have this part correct but I can't seem to get this next part.

    If there are 2 used and 7 new wrenches, what is the probability that a particular line (line A) gets both used?

    Here the answer is 1/12
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  2. #2
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    Quote Originally Posted by dwsmith View Post
    3 lines are to divide up 9 wrenches evenly.
    What is the world does that statement mean?
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    Quote Originally Posted by Plato View Post
    What is the world does that statement mean?
    Assembly lines.
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  4. #4
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    The answer \dfrac{9!}{(3!)^3} is the number of ways to divide nine people, two adults and seven children, into three different activates of three each.
    If we want the two adults in a particular same activity, that can be done is one way and seven ways to pick the one child.
    How many ways to assign six children to two actives of three each?
    Last edited by Plato; January 27th 2011 at 02:15 PM.
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