in how many ways can a committee of five be selected from 8 women and 5 men.
a) without restriction
b) if there must be three women on the committee
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in how many ways can a committee of five be selected from 8 women and 5 men.
a) without restriction
b) if there must be three women on the committee
a) There are 13 people to choose from and you must choose 5.Quote:
Originally Posted by johnsy123
So the number of combinations of 5 people from 13 is.
For part b) does that mean there must be EXACTLY three women or AT LEAST three women?
never mind guys, i worked it out. :)
You're welcome :P
Your working out is wrong, because you can't simply work out the number of combinations as there are independent variables, so what i did is i worked out the combinations of which you can variate 4 men and 8 women into a committee of 5, there were 5.
-If i knew how to use the symbols on MHF, i would show you what i done.
But there are 5 men... And since you're choosing any 5 people out of those 13, it doesn't matter how many men and women there are. It's just the number of ways you can pick 5 people from 13, i.e.Quote:
Originally Posted by johnsy123
.
I agree.Quote:
Originally Posted by Prove ItBut there are 5 men... And since you're choosing any 5 people out of those 13, it doesn't matter how many men and women there are. It's just the number of ways you can pick 5 people from 13, i.e.
I assume the OP no longer needs (or no longer thinks s/he needs) help with part (b) ....?