no of ways of dividing 15 men and 15 women into 15 couples each consisting of men and women
Follow Math Help Forum on Facebook and Google+
The first man can be paired with any of the 15 women, the second man with any of the remaining 14 women and so on. So the total no of ways is 15x14x...x1=15!.
but the answer is coming out to be 1240
Originally Posted by prasum but the answer is coming out to be 1240 $\displaystyle 15!=1307674368000$
View Tag Cloud