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**Discrete** Let (S, $\displaystyle \preceq $) be a poset. We say that an element y $\displaystyle \in $ S covers an element x $\displaystyle \in $ if x $\displaystyle \prec $ y and there is no element z $\displaystyle \in $ S such that $\displaystyle x \prec y \prec z $. The set of pairs (x,y) such that y covers x is called the covering relation of (S, $\displaystyle \preceq $) What is the covering relation of the partial ordering {(a,b) $\displaystyle \vert $ a divides b} on {1,2,3,4,6,12}?

My answer so far is {(1,2), (1,3), (2,4), (2,6), (3,6), (4,12), (6,12)}is this right?