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Thread: Sets

  1. July 8th 2007, 06:10 PM #1
    computer-bot
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    Sets

    please explain the question in the attached picture.

    CB
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  2. July 8th 2007, 06:45 PM #2
    le_su14
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    Quote Originally Posted by computer-bot View Post
    please explain the question in the attached picture.

    CB
    (A \cap B) \cup (A-(A \cap B)) = A
    Because : (A \cap B) and (A-(A \cap B)) are mutually exclusive .
    So , P((A \cap B) \cup A-(A \cap B)) = P(A \cap B) + P(A-(A \cap B)) = P(A)
    and , P(X) >= 0 , with every events .
    Therefore , P(A \cap B) =< P(A)
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