# Sets

• Jul 8th 2007, 06:10 PM
computer-bot
Sets
please explain the question in the attached picture.

CB
• Jul 8th 2007, 06:45 PM
le_su14
Quote:

Originally Posted by computer-bot
please explain the question in the attached picture.

CB

$(A \cap B) \cup (A-(A \cap B)) = A$
Because : $(A \cap B) and (A-(A \cap B))$ are mutually exclusive .
$So , P((A \cap B) \cup A-(A \cap B)) = P(A \cap B) + P(A-(A \cap B)) = P(A)$
and , $P(X) >= 0$, with every events .
Therefore , $P(A \cap B) =< P(A)$