Find the sum when n=1000. Show all your steps. Use the properties of summation. i=1 -->n ((4i/n^2)+(i^3/n))*(6/i) Thank you very much....I hope I hear back asap!!!
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You're performing this sum, then? If so, I would note two things: 1. You can simplify a bit before summing. 2. It's true from principles of induction that So what does that tell you?
Thank you so much...you saved me!!!!
You're welcome. You have solved it, then?
No I did not sadly, and it is due in one hour. Can you direct me anymore?
If it's "due", then it is for a grade, right? Forum policy is not knowingly to help with graded problems.
"Due" was not the right word. Sorry this is the first time I have used this site. It is a practice problem given before our classes. My apologies, thanks for that information. Not for a grade.
Well, what simplifications do you get?
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