Originally Posted by

**Thetheorycase** The problem

*n*

Σi^2 = *n*(*n *+ 1)(2*n *+ 1)/6

*i*=1

The base case is correct. Gona get to the meat of the problem

P(k) -------> P(k +1)

1^2 + 2^2 + 3^2 ......+k^2 = k(k +1)(2k+ 1)/6

Now showing k +1

1^2 + 2^2 + 3^2 ......+k^2 + (K +1)^2 = k+1((k +1)+1)((2k+ 1)+1)/6

RHS = **(2k^3 + 7k^2 + 10k + 6)/6**

LHS =

1^2 + 2^2 + 3^2 ......+k(k +1)(2k+ 1)/6 + (K +1)^2

Before I go on was I right in mulitplyong everything out with k +1 on the RHS so i could math it up with the LHS? in bold

Thank you!!