# Thread: General and subsets

1. Originally Posted by hellfire127
ok so 6 is true by what i did on first post? then what did you mean by the reverse inclusion? that F(A)⋂(FB)=F(A⋂B) is false right?
The reverse inclusion $F(A)\cap F(B)\supseteq F(A\cap B)$ is not true.

2. Originally Posted by Drexel28
The reverse inclusion $F(A)\cap F(B)\supseteq F(A\cap B)$ is not true.
ok i think i see what you mean now. the = in the problem means it's both ways. so i have proven one way which is true but the reverse inclusion is not true. so the answer for number 6 is NO.

now do i have to do the reverse inclusion for number 7 as well?

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