From the integers:1,3 ,9,27,81,243,729... I have: The sum from k=0 to infin of 3^k times x^k. How do I incorporate the geometric series into this and finish this problem?
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Originally Posted by guyonfire89 From the integers:1,3 ,9,27,81,243,729... I have: The sum from k=0 to infin of 3^k times x^k. How do I incorporate the geometric series into this and finish this problem? $\displaystyle \displaystyle \sum_{k=0}^{\infty}3^kx^k=\sum_{k=0}^{\infty}(3x)^ k$ So if $\displaystyle 3x<1$ you have a convergent infinite geometric series. CB
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