# Thread: Another ''36 sweets'' counting problem ???

1. ## Another ''36 sweets'' counting problem ???

This is similar to a problem that I've already posted here before. Infact its the second part to that problem. I decided to start a new thread. Apologies if I should haved added it to the existing thread.

36 sweets are to be divided among 6 individuals. How many ways can they be divided such that each individual receives at least 3 AND no more than 7 sweets?

Any hints as to how this problem should be solved would be appreciated.

2. This is not a straightforward counting question.
It can easily be done with generating functions.

Go to this website.

The coefficient of $x^{36}$ is the answer to the question.

3. 426?

Thats much smaller than what I've calculated. I tried doing the question and got 15,946 ways. (Although how I got this number is an altogether different discussion :P)

4. Originally Posted by Markhor
426?
Thats much smaller than what I've calculated. I tried doing the question and got 15,946 ways. (Although how I got this number is an altogether different discussion :P)
But you must remember that the at most seven really complicates it answer.