Heres a proof I am getting stuck with
Prove sqrt(p) is irrational, p is set of all primes
so heres what Ihave
prove sqrt(p) is rational
sqrt(p) = a/b a,b set of integers, b not equal to 0, and a/b is in lowest form
p = a^2/b^2
p*b^2 = a^2.
a^2/p = b^2.
a/sqrt(P) = b
Kind of at a standstill here, since b cannot be rational when dividing by the sqrt of a prime. how can I say this?