general solution of a recurrence relation

**dunsta** · October 17th 2010, 09:09 PM

Hi
Is this the correct general solution for the following recurrence relation
$0 = a_{n+2} + a_{n+1} - 12a_{n}$

$x^2 + x -12 = 0$
(x+4)(x-3) = 0
x = -4, x = 3

Therefore the general solution is
$a_n = A-4^n + B3^n$
where A and B are arbitrary constants

*I'm not sure if it's ok to have the negative in there.

Thanks for any time + help

**pickslides** · October 17th 2010, 09:16 PM

Originally Posted by dunsta

Therefore the general solution is
$a_n = A-4^n + B3^n$
where A and B are arbitrary constants

*I'm not sure if it's ok to have the negative in there.

The general solution is $a_n = A\times (-4)^n + B\times 3^n$

**dunsta** · October 17th 2010, 09:55 PM

Thanks Pickslides, I really can't thank you and the other regulars, who have helped and tutored me via this forum, enough.

Thread: general solution of a recurrence relation

LinkBack

Thread Tools

Display

general solution of a recurrence relation

Similar Math Help Forum Discussions

Closed-form solution of a recurrence relation.

General solution to 3rd order recurrence relation

f(n) general term of recurrence relation

HELP with Particular solution in the non-homogeneous recurrence relation

Find solution to a recurrence relation...

Search Tags