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Math Help - general solution of a recurrence relation

  1. #1
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    general solution of a recurrence relation

    Hi
    Is this the correct general solution for the following recurrence relation
    0 = a_{n+2} + a_{n+1} - 12a_{n}

    x^2 + x  -12 = 0
    (x+4)(x-3) = 0
    x = -4, x = 3

    Therefore the general solution is
    a_n = A-4^n + B3^n
    where A and B are arbitrary constants

    *I'm not sure if it's ok to have the negative in there.

    Thanks for any time + help
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  2. #2
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    Quote Originally Posted by dunsta View Post

    Therefore the general solution is
    a_n = A-4^n + B3^n
    where A and B are arbitrary constants

    *I'm not sure if it's ok to have the negative in there.
    The general solution is a_n = A\times (-4)^n + B\times 3^n
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  3. #3
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    Thanks Pickslides, I really can't thank you and the other regulars, who have helped and tutored me via this forum, enough.
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