Let be a graph with average degree . Show that there exists a vertex such that the average degree of neighbours of is at least .

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- Oct 14th 2010, 10:14 AMNewtonianGraph Theory Puzzle
Let be a graph with average degree . Show that there exists a vertex such that the average degree of neighbours of is at least .

- Oct 19th 2010, 02:31 PMNewtonian
Does anyone have any ideas? Incidentally, there does not necessarily have to exist a vertex such that the average degree of neighbours is at most d, so I think there is at least something slightly subtle going on...