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Thread: Composite numbers

  1. October 12th 2010, 08:29 PM #1
    nurdynik
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    Composite numbers

    For n > 2, show that all of the numbers

    n! + 2, n! + 3,......., n! + n

    are composite numbers.
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  2. October 12th 2010, 08:39 PM #2
    tonio
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    Quote Originally Posted by nurdynik View Post
    For n > 2, show that all of the numbers

    n! + 2, n! + 3,......., n! + n

    are composite numbers.


    If k\leq n\,,\,\,then\,\,n!+k=1\cdot 2\cdot \ldots\cdot k\cdot\ldots\cdot n+k is divisible by k...

    Tonio
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« Where did I go wrong on this proof? (Mathematical Induction) | Calculating the number of possible outcomes »

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