If a|m and b|m, does that mean a*b|m?

ak=m

bj=m

$\displaystyle akbj=m^2$

$\displaystyle ab(kj)=m^2\rightarrow ab \left(\frac{kj}{m}\right)=m$

Is this how it would be shown?

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- Oct 9th 2010, 03:35 PMdwsmitha|m and b|m does that mean a*b|m?
If a|m and b|m, does that mean a*b|m?

ak=m

bj=m

$\displaystyle akbj=m^2$

$\displaystyle ab(kj)=m^2\rightarrow ab \left(\frac{kj}{m}\right)=m$

Is this how it would be shown? - Oct 9th 2010, 03:39 PMJhevon
- Oct 9th 2010, 07:16 PMmathdigger
@dwsmith:

The fault with your argument is that you don't know whether kj/m would come out to be an integer or not.