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The statement is:
"For each real number p, there exist real numbers q and r such that qsin(r/5) = p."
We have to either prove this statement or give a counter-example.
I've been talking with others in my class and it seems like the first thing we need to do is say:
"Let p be a real number. Put r = (5/2)(pi)."
And then I plugged this in for r in the equation, getting q = p.
Is this correct? If not, what am I doing wrong? Thanks in advance for the help :)
That is exactly what I would do.Quote:
Originally Posted by Lprdgecko
Additional note: I would start out by writing "Let q = p and r = (5/2)pi. Then...."
So, I am a little confused on what we are trying to prove. Do we need to prove that q = p or are we proving that qsin(r/5) = p?Quote:
Originally Posted by undefined
I added an additional note to my first post, not quickly enough I guess. Let me know if it's still not clear.Quote:
Originally Posted by Lprdgecko
I see the note now. So, after setting q = p and r = (5/2)pi, then is it as simple as saying "Then, qsin(r/5) = p" or would we have to to actually plug in the values (and show that part in the proof) to prove that fact?Quote:
Originally Posted by undefined
I would plug in, just for clarity and to demonstrate you understand it all. Hardly takes any extra time.Quote:
Originally Posted by Lprdgecko
Ok, thank you so much!Quote:
Originally Posted by undefined
You're welcome!Quote:
Originally Posted by Lprdgecko