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Math Help - Boolean Algebra

  1. #1
    Junior Member
    Joined
    Jun 2010
    Posts
    69

    Boolean Algebra

    Hi

    Can anyone expalin to me how
    x'y'z' + x'yz' + xyz'
    = x'z' + yz'

    I can only reach this:
    x'y'z' + x'yz' + xyz'
    =(y'+y)x'z' + xyz'
    =x'z' + xyz'

    where do I go next?

    Thanks for your time.

    EDIT:
    Can you repeat an expression from the original equation
    i.e. in the equation x'y'z' + x'yz' + xyz' (there are 3 xyz variables)
    if I use
    x'y'z' + x'yz' = (y+y')x'z' = x'z'
    x'yz' + xyz' = (x+x')yz' = yz'
    then
    result = x'z' + yz'

    is this ok?
    Last edited by dunsta; September 28th 2010 at 09:50 PM.
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  2. #2
    MHF Contributor
    Joined
    Oct 2009
    Posts
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    Thanks
    778
    Yes, the fact that a = a + a is derivable from Boolean algebra axioms (or sometimes is taken as an axiom).
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