Thread: Counting Principle 52-card deck

How many ways are there to pick 2 different cards from a standard 52-card deck such that:

The fist card is a spade and the second card is not a Queen

The answer is (1*48) + (12*47)

I do not know how to get there again.

I have 13 spade cards in a 52-card deck
Ace, 2,3,4,5,6,7,8,9,10, Jack, Queen, King

so I thought there are 13 possibilities for the first card
For the second card we cannt have Queens (4) and one card is already gone,
so that would be 52-4 - 1 = 47

I see the problem that maybe for the first card a spade Queen was used, but I do not know how to set the problem up with this information.

Thanks for any hint.

Hello, DBA!

How many ways are there to pick 2 different cards
from a standard 52-card deck such that:

The first card is a Spade and the second card is not a Queen.

The answer is: .

We must consider two cases:

. . (1) the first card is the

. . (2) the first card is not the


(1) The first card is the .
. . . There is one way to accomplish that.

. . . Among the other 51 cards, there are 3 Queens and 48 Others.
. . . And we want one of the Others: 48 ways.

. . . Hence: .


(2) The first card is a , but not the
. . . There are 12 ways to accomplish that.

. . . Among the other 51 cards, there are 4 Queens and 47 Others.
. . . And we want one of the Others: 47 ways.

. . . Hence: .


Therefore: .