How many arrangements of letters of word TRANSITION are possible if
the Is and Ns and Ts are together.
Here is my attempt:
Group Is, Ns, and Ts together, and arrange: 5! ways
Arrange amonst Is, Ns, Ts, removing repeition: 6! / 2!2!2!
This is not what the book has, which contains 5040 as answer.
Hello, Lukybear!
undefined is absolutely correct.
Since the double-letters are to be adjacent, duct-tape them together.
Then we have 7 "letters" to arrange: .
Therefore, there are: . arrangements.
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
I see another interpretation of this problem.
It should have said: .
Instead it said: "The I's and N's and T's are together."
. . which could mean that we have, for example,
. . somewhere in the arrangement.
So we have 5 "letters" to arrange: .
. . There are: . ways.
But can be arranged in: .
Therefore, there are: . arrangements.