Theorem
supexists
inf
exists
Proof:
exists
Now we show that
Show that
1.is a lower bound of
.
2. ifis a lower bound of
-sup
1.
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is an upper bound of
![]()
![]()
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is a lower bound of
(line added for correction 6:30 a.m. Sep 12)
2. Suppose thatis a lower bound of
suppose not![]()
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on the other hand
<------(Could someone tell me how this come about.)
Hence,is an upper bound of
By 1. & 2,&
=
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