Show that gcd (a, m) gcd(a, mn) for any integers a,m and n.
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Originally Posted by Statsnoob2718 Show that gcd (a, m) gcd(a, mn) for any integers a,m and n. Sometimes gcd(0,0) is defined as 0 which would provide an exception, but aside form that, show that gcd(a,m) | gcd(a,mn).
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