Inverse Image Intersection Equality and Counterexample of a Function Proof
Suppose f is a function with sets A and B.
1. Show that:
2. Show by giving a counter example that:
Let c be an element of .
By the definition of , there is a so that .
Since, , . Since . This follows alongside .
Since and .
Thoughts? Also would I need to show that the to show true equality?
I'm thinking either the absolute value function or a square function of some sort would show that it is not equal. Though, I'm not sure how to proceed with depicting the counter example.