Use induction to show that: (1+x) E (n, i=0) (-x)^i = 1 + x^(n+1) The E (n, i=0) bit is the summation notation with the n on top and i=0 on the bottom, you know?
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Originally Posted by brumby_3 Use induction to show that: (1+x) E (n, i=0) (-x)^i = 1 + x^(n+1) The E (n, i=0) bit is the summation notation with the n on top and i=0 on the bottom, you know? I assume you meant you want to show I leave the base case to you. Suppose your assertion is true for i.e. Now Can you finish up from here?
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