If $\displaystyle n\ge 0$, show that
$\displaystyle \displaystyle \sum_{k=0}^{n}\binom{2n}{k}\binom{2n-2k}{n-k} = \sum_{k=0}^{n}\binom{2n+1}{k} = \sum_{k=0}^{2n}\binom{2n}{k}$
Printable View
If $\displaystyle n\ge 0$, show that
$\displaystyle \displaystyle \sum_{k=0}^{n}\binom{2n}{k}\binom{2n-2k}{n-k} = \sum_{k=0}^{n}\binom{2n+1}{k} = \sum_{k=0}^{2n}\binom{2n}{k}$
The first one seems to the the odd one out. The last two evaluate to the same closed form expression. I suppose there is a typo in the first sum.