• August 9th 2010, 10:59 AM
ducktales
An amazing BLC tournament is taking place at the moment. A total of 97 teams competing each other to determine the champ. It's sponsored by theShrimp and the winning team will win one invite to the closed beta http://www.bloodlinechampions.com/fo...con_e_wink.gif. The way the winner is chosen for this tournament is the well known elimination schedule. That means, all 97 teams are devided into pairs, those two teams of each pair fight against each other. It's standard pick mode, everyone plays the bloodline he wants to, no restrictions. After a team is kicked out from each pair, the winners would be again divided into pairs...

How many games must be played to determine the Bloodline "Champion"?

• August 9th 2010, 11:45 AM
Soroban
Hello, ducktales!

Are we supposed to be familiar with the Shrimp and various bloodlines?
Does any of this affect the elimination tournament?

Quote:

An amazing BLC tournament is taking place at the moment.
A total of 97 teams competing to determine the champion.
It's sponsored by the Shrimp and the winning team
. . will win one invite to the closed beta. .?

The winner is chosen by the well-known elimination schedule.
That means, all 97 teams are devided into pairs.
The two teams of each pair fight against each other.
It's standard pick mode, everyone plays the bloodline he wants to, no restrictions. .?
After a team is eliminated from each pair, the winners would be again
. . divided into pairs . . . and so on.

How many games must be played to determine the champion?

BTW the answer is NOT 94 or 93...I was told it's higher.

Since 97 cannot be divided by 2,
. . there must be 48 pairs and one player gets a "bye".

. . $97 \;=\;2(48) + 1$ . . . 48 games are played.

. . There are 49 players remaining.

We have: . $49 \;=\;2(24) + 1$ . . . 24 game are played.

. . There are 25 players remaining.

We have: . $25 \;=\;2(12) + 1$ . . . 12 games are played.

. . There are 13 players remaining.

We have: . $13 \;=\;2(6) + 1$ . . . 6 games are played.

. . There are 7 players remaining.

We have: . $7 \;=\;2(3) + 1$ . . . 3 games are played.

. . There are 4 players remaining.

We have: . $4 \;=\;2(2)$ . . . 2 games are played.

. . There are 2 players remaining.

We have: . $2 \;=\;2(1)$ . . . 1 game is played.

. . The remaining player is the Champion.

Therefore: . $48+24+12+6+3+2+1 \;=\;\boxed{96}$ games are played.