Consider the function f: N --> R defined by f(0) = 2 f(n+1) = f(n) + n - 2 Compute f(1), f(2), f(3). I know how to do this, but I was just wondering what is "n" - I mean f(n) for f(1) is 2, but is n just 1 for f(1) or 0?
Follow Math Help Forum on Facebook and Google+
Originally Posted by brumby_3 Consider the function f: N --> R defined by f(0) = 2 f(n+1) = f(n) + n - 2 Compute f(1), f(2), f(3). I know how to do this, but I was just wondering what is "n" - I mean f(n) for f(1) is 2, but is n just 1 for f(1) or 0?
Originally Posted by Plato Thank you Plato!
For make you get Now make
Thanks pickslides, I've got it
View Tag Cloud