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Math Help - Function question

  1. #1
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    Function question

    Consider the function f: N --> R defined by
    f(0) = 2
    f(n+1) = f(n) + n - 2

    Compute f(1), f(2), f(3).

    I know how to do this, but I was just wondering what is "n" - I mean f(n) for f(1) is 2, but is n just 1 for f(1) or 0?
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  2. #2
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    Quote Originally Posted by brumby_3 View Post
    Consider the function f: N --> R defined by
    f(0) = 2
    f(n+1) = f(n) + n - 2

    Compute f(1), f(2), f(3).

    I know how to do this, but I was just wondering what is "n" - I mean f(n) for f(1) is 2, but is n just 1 for f(1) or 0?
    f(1)=f(0+1)=f(0)+0-2~\&~f(2)=f(1+1)=f(1)+1-2
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  3. #3
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    Quote Originally Posted by Plato View Post
    f(1)=f(0+1)=f(0)+0-2~\&~f(2)=f(1+1)=f(1)+1-2
    Thank you Plato!
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  4. #4
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    For f(n+1) = f(n) + n - 2 make n=0 you get

    f(0+1) = f(0) + 0 - 2 \implies f(1) = 2 + 0 - 2 = 0

    Now make n=1
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  5. #5
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    Thanks pickslides, I've got it
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