Originally Posted by
brumby_3 Consider the function f: N --> R defined by
f(0) = 2
f(n+1) = f(n) + n - 2
Compute f(1), f(2), f(3).
I know how to do this, but I was just wondering what is "n" - I mean f(n) for f(1) is 2, but is n just 1 for f(1) or 0?