If f: {a1,...,a6} -> P is defined by f(ai) equals the set containing ai, explainCode:Let S = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12}. Someone gives you six numbers a1,....,a6 from S. Let P = {{x, y} | x, y Œ S and x + y = 15}
why f is not one-one.
If ai != (does not eqaul) aj but f(ai) = f(aj) show that ai + aj = 15.
Explain why, if 6 numbers are chosen from S then the sum of some pair of them
is 15.
Can someone help me
Cheers
For starters, I would recommend writing out the set explicitly. Also, one has to understand whyis a correct definition of a function. By this I mean why for any there exists an (unordered) pair from such that and why such is unique.is defined by equals the set containing