Hi

To graph in the cartesian plane

a --->$\displaystyle x^2+y^2 = 9$

would that be a graph where the x,y co-ordinates are (0,0) and the radius of the circle on the graph is 3 ???

(btw, while I know $\displaystyle 0^2+0^2 != 3^2$ the only example I have is an equation where $\displaystyle (x-10)^2 + y^2 = 16$, therefore (x,y) co-ords are (10,0) and radius is 4. From this I deduce the results from the equation above (a))

b ---> $\displaystyle x<=y$ has co-ords (x,y) = (0,0), which is a diagonal line through the intersection of x and y, from top right to bottom left, shaded area on upper side marking x<=y???

am i on the right track?