
Cartesian plane
Hi
To graph in the cartesian plane
a >
would that be a graph where the x,y coordinates are (0,0) and the radius of the circle on the graph is 3 ???
(btw, while I know the only example I have is an equation where , therefore (x,y) coords are (10,0) and radius is 4. From this I deduce the results from the equation above (a))
b > has coords (x,y) = (0,0), which is a diagonal line through the intersection of x and y, from top right to bottom left, shaded area on upper side marking x<=y???
am i on the right track?

Seems you are wrong.
from we mean set of points (x,y) on the 2d carteisian plane which satisfiy the given equation. (0,0) definately doesn't belong to this graph.

I'm just guessing,
but would this work?
then x = 0 and y = 3
??

No, not even close

Well, i have no idea then
I would have thought
if x = 3, or 3
then y = 0
or if
y = 3 or 3
then
x = 0
because
or any combination with 3, 3 and 0
so the points on the graph could be
(3,0), (3,0), (0,3), (0,3)
i wish I could draw it here, but basically it looks like a circle with center (0,0) and radius 3. (i am sure you can picture what I mean)
I don't know how else to approach it?
edit (sorry in my original post I said the x,y coords are (0,0) but now see this is the center and not the (x,y) coordinates)

yes  [tex]x^2+y^2 = 9[\math] is a circle with raidus = 3 and center = (0,0)
so all the points you said
(0,3),(0,3),(3,0),(3,0)
are on the circle and there are many more
But note (0,0) is not on that circle.

aman_cc and pickslides thank you very much.